/**
 * Finds the index of the last occurrence of a value in a sorted array.
 * This function is similar to `Array#lastIndexOf` but is specifically designed for sorted arrays.
 *
 * Make sure to provide a sorted array to this function, as it uses a binary search to quickly find the index.
 *
 * @param {ArrayLike<T> | null | undefined} array The sorted array to inspect.
 * @param {T} value The value to search for.
 * @returns {number} Returns the index of the last matched value, else -1.
 *
 * @example
 * const numbers = [1, 2, 3, 4, 5];
 * sortedLastIndexOf(numbers, 3); // Return value: 2
 * sortedLastIndexOf(numbers, 6); // Return value: -1
 *
 * // If the value is duplicated, it returns the last index of the value.
 * const duplicateNumbers = [1, 2, 2, 3, 3, 3, 4];
 * sortedLastIndexOf(duplicateNumbers, 3); // Return value: 5
 *
 * // If the array is unsorted, it can return the wrong index.
 * const unSortedArray = [55, 33, 22, 11, 44];
 * sortedLastIndexOf(unSortedArray, 11); // Return value: -1
 *
 * // -0 and 0 are treated the same
 * const mixedZeroArray = [-0, 0];
 * sortedLastIndexOf(mixedZeroArray, 0); // Return value: 1
 * sortedLastIndexOf(mixedZeroArray, -0); // Return value: 1
 *
 * // It works with array-like objects
 * const arrayLike = { length: 3, 0: 10, 1: 20, 2: 20 };
 * sortedLastIndexOf(arrayLike, 20); // Return value: 2
 */
declare function sortedLastIndexOf<T>(array: ArrayLike<T> | null | undefined, value: T): number;

export { sortedLastIndexOf };